gdaunton Posted February 11, 2014 Share Posted February 11, 2014 Hello, I got to this question and was not sure how to go about it. I sorta had an idea but that was for the line charge of a fixed length, so do I just ignore the lengths and assume that E= lamda/(4 pi e0) and then use V=int(E*dl)? 1 Quote Link to comment Share on other sites More sharing options...
0 FizziksGuy Posted February 12, 2014 Share Posted February 12, 2014 Good strategy, but the electric field due to a line of charge isn't lambda/(4 pi e0). Use Gauss's law to derive it. It's in your notes, in the Gauss's Law video, and also in the course guides. Quote Link to comment Share on other sites More sharing options...
0 gdaunton Posted February 12, 2014 Author Share Posted February 12, 2014 So I should get (-lamda*r)/(2*pi*e0)+c for the electric potential right? Quote Link to comment Share on other sites More sharing options...
0 FizziksGuy Posted February 12, 2014 Share Posted February 12, 2014 Looks like your integration is off a bit... More math here, then: From there you just substitute in your specific values for the distance from the line and the reference distance (2.5m) Quote Link to comment Share on other sites More sharing options...
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gdaunton
Hello,
I got to this question and was not sure how to go about it. I sorta had an idea but that was for the line charge of a fixed length, so do I just ignore the lengths and assume that E= lamda/(4 pi e0) and then use V=int(E*dl)?
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