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A recap on Gauss' Law


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Gauss' Law is a topic that we covered in Physics-C that was pretty much completely new to us. We didn't talk about it about all in Physics-B, so it's one of the harder things we have to do in Physics-C this year.

Because of this, for myself and for others, I want to type up some of the derrivations and notes so that its fresh in my mind and can maybe help some other people who need it!

The equation to remember:

png.latex? \phi =\oint \underset{E}{\rig

When you have a conducting sphere with uniform charge Q and radius R:

1. r < R

png.latex? \oint \underset{E}{\rightarro

png.latex? E\oint \underset{dA}{\rightar

png.latex? E(4\pi r^{2})=\frac{0}{\epsil

png.latex? E=0

2. r > R

png.latex? \oint \underset{E}{\rightarro

png.latex? E(4\pi r^{2})=\frac{Q}{\epsil

png.latex? E=\frac{Q}{\epsilon _{0}(4\pi

png.latex? E=\frac{kQ}{r^{2}}

When you have an infinite plane with charge density of png.latex?\sigma

The First step is to assume that there is a finite cylinder that comes out of either side of the infinite plane. This will help with the derrivation and any dimmensions of the cylinder will later cancel.

png.latex? \phi =\oint \underset{E}{\rig

png.latex? \sigma =\frac{Q}{A}

png.latex? \phi _{top}+\phi _{bottom}=\f

png.latex? EA+EA=\frac{\sigma A}{\epsilo

png.latex? 2E=\frac{\sigma }{\epsilon _{

png.latex? E=\frac{\sigma }{2\epsilon _{

For 2 infinite planes that are uniformly charged, one is png.latex? +\sigma and the other is png.latex? -\sigma , the electric fields point in the same direction, so you have:

png.latex? E=\frac{2\sigma }{2\epsilon _

And therefore, the electric field in an infinite capacitor is

png.latex? E=\frac{\sigma }{\epsilon _{0

Hope this blog helps... at the very least all this makes sense to me now (finally)! just wish i had done this before the test :P

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I really like doing these derrivations - so if anyone has any requests, send them my way!

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