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The Physics of Swings


bazinga818

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Hello, world of AP Physics C. I'd like to talk to you about the physics of swings today.

Swingsets involve circular motion! If you think about it, when you swing you're actually completing a half circle each time you swing to and from your highest points. At your lowest point (the bottom of the circle), the tension (T) from the chains is pulling upwards, and your weight (mg) is pulling downwards. The centripetal acceleration (v^2/r), as well as the centripetal force (mv^2/r, using Newtons Law F=ma) both point towards the center of the circle. Therefore, to find the tension at the bottom of the circle, one would use the equation T=(mv^2/r) + mg. At either side of the circle, since tension and Fc point inward and weight is downward, the equation would be T=mv^2/r.

If you had a great enough velocity (which points tangentally to the circle, perpendicular to the Fc and ac (cent. accel.)), you might be able to swing all the way around the top of the swingset. For this to happen, the tension would have to be a minimum of zero newtons. At the top of the circle, since both tension and weight point downward (as well as Fc), the equation to find tension would be T=(mv^2/r) - mg.

Now you know about the physics of swingsets! I've included a few pictures below to further your comprehension, if my explanations weren't explanatory enough. Thanks for reading, see ya next week! :thumbsu:

bazinga818 :ass:

http://www.ic.sunysb.edu/Class/phy141md/lib/exe/fetch.php?media=phy141:lectures:ballonstring.pngn16.jpgcub_pend_lesson01_image1.jpg

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