If you have seen part 1, then you may know where I will be getting some of my information down. This time we will be talking about the use of wheel barrows. The wheelbarrow is designed to distribute the weight of its load between the wheel and the operator so enabling the convenient carriage of heavier and bulkier loads than would be possible were the weight carried entirely by the operator. Because of the design we can use the equation Torque=FL.
The wheel barrows can carry 6 planks, with each being 6.8kg, that is a total of 40.8kg. If that force is applied .3 meters away from the fulcrum, and the force to exerted by the user is .75 m away from the fulcrum. That means that the 40.8 kg which excerts a force of 400.25 N will only require 160.1 N to lift. If we want to find the work with this force and Part 1's Distances, we find that in the x-plane, we use about the same force, so we exert the same 60000 joules, but now in the y-plane, we only exert 16010 joules. A significant difference than from part 1, and this allows twice as many boards.
Due to this difference, I mainly used wheel barrows to carry the 90 planks down the trail. Next time we will look at Sledge hammers.