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WA gripe of the night



im doing this problem: A horizontal force of 161 N pushes a 6 kg block up a frictionless incline that makes an angle of 27° with the horizontal...find the normal force. Okay well according to every physics lesson i know and mr F's notes online the component of gravty opposite the normal force is mgcos(angle). so id did (6kg)(9.8m/s^2)cos(27). That gets you 52.39 and WA says thats wrong. i disagree. Also, looking at a practice problem, the answer they provided was greater than what the normal force would have been if the object was on level ground....ive wasted 45 minutes on this problem and i think web assign (expicitive) it up.


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The key here is realizing the force applied is horizontal... then, using the data you gave me, you can put it all together so your answer looks something like this!


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