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WA gripe of the night

ThatGuy

Entry posted by ThatGuy

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im doing this problem: A horizontal force of 161 N pushes a 6 kg block up a frictionless incline that makes an angle of 27° with the horizontal...find the normal force. Okay well according to every physics lesson i know and mr F's notes online the component of gravty opposite the normal force is mgcos(angle). so id did (6kg)(9.8m/s^2)cos(27). That gets you 52.39 and WA says thats wrong. i disagree. Also, looking at a practice problem, the answer they provided was greater than what the normal force would have been if the object was on level ground....ive wasted 45 minutes on this problem and i think web assign (expicitive) it up.

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FizziksGuy

The key here is realizing the force applied is horizontal... then, using the data you gave me, you can put it all together so your answer looks something like this!

image_thumb21.png

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