Jump to content
  • entries
    29
  • comments
    28
  • views
    4,041

Linear* Momentum of the Earth


BrandyBoy72

6,250 views

P=MV

Momentum of the Earth (Linear):

Mass of the Earth: 5.972*10^24 kg  ;  the weight of the Earth is measured using the equation FG=(Gm1m2)/r2 taking an object that has mass and finding the force that the Earth exerts on it.

Velocity of the Earth: 30000 m/s  ;  We find the velocity of the Earth by knowing that the Earth travels around the Sun in one year, now we only have to find how far it travels. We have to find the length of its ellipse around the sun, which is approximately a circle (or close enough - this is physics after all where 9.8=10...) So we have to find the radius which is the average distance from the Sun to the Earth which is known as an Astronomical Unit (AU) which is 149,600,000 km. So C=2*pi*r2 ; C=2*pi*(149,600,000,000m)2  and divide that by one year to get the velocity.

Now multiply mass and velocity together to get momentum:   5.972*10^24kg * 30000m = 1.7916*10^29 N*S - pretty big

2 Comments


Recommended Comments

Sorry  BrandyBoy72  ... but you got your circumference and area formulae mixed up!

Circumference of a circle = 2πr not 2πr  !!

Area of a circle = πr

 

Xavier

June 2021

Link to comment
Guest
Add a comment...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...