t_hess10
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There are many examples of waves in our daily lives, such as water waves, earthquakes, and radiation. Although these might be different types of waves, they all have one thing in common- they all have wave speed. You can determine wave speed with the equation, s=f(lambda). S represents the wave speed, f represents the frequency, and lambda represents the wave length. As an example, if you were looking at a side view of water waves on a beach and the distance between to wave crests was 10 meters, and .5 waves pass every second, your able to solve for wave speed. By using the equation given, multiply (10m)(.5Hz), which will equal a wave speed of 5m/s. Overall, wave speed is very simple to solve for when you know the wavelength and frequency of a wave.
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In the study of waves, there's many different types of waves. First, there are mechanical waves, such as sound, water, and seismic waves, which all require a medium to travel through. In contrast, there are electromagnetic waves, such as visible light and x-rays, which all don't require a medium. Also, when looking at waves, the crest is the top, such as the top of a wave on a beach, and the bottom is called a trough. The length between two crests is known as a wavelength and the amplitude is the distance from a medium to the crest, or to the trough. Also, waves have a frequency, which the number of waves in one second, and the period, which is the time of one wave.
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When knowing the way magnets act with each other when in close proximity, you can determine many ways other objects act around them. First, if a magnet runs north to south with the north side of the magnet on the left side of a picture and a compass above the magnet, your able to determine the direction of the compass. Since compass's point in the direction of the magnet field line and the magnets' magnetic field lines run from north to south, the compass would be pointing to the right, since it was above the magnet. Also, a magnetic field strength is greatest when in the most dense area of magnetic field lines. Lastly, the greatest strength of an electromagnet is if it's wrapped in iron. Overall, there's many problems you can solve with magnets, knowing how they act alone and around other magnets.
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In magnets, there are many rules to need to know. First magnets run from north to south outside the magnet and south to north inside the magnet. Also, magnetic field lines show the flow of these electrons and how they interact with other magnets around. When two magnets are close to each other with both of their closest sides the same, the magnets repel each other and magnet field lines shown in between the magnets are seen repelling away from each other. Also, when two magnets are close to each other with their closest sides being opposite, they attract, which is shown with magnetic field lines. Overall, by using these need to knows, you can determine many question with magnets.
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VIRP tables are the best use to find missing information in either series circuits or parallel circuits. However, there's different rules for each type of circuit. First, in a series circuit, all the currents are the same for the total and each resistor. However, the voltage is the same for all resistors and the total in parallel circuits. Also, in a parallel circuit, to solve for the resistance, the addition of 1/each resistor equals 1/total resistance. Lastly, to find missing information, you can use both R=V/I and P=IV. Overall, when using the VIRP table, you can solve any resistor circuit problem given.
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Although I described the importance of Newton's laws in retrospect to baseball, I have learned many more connections between physics and the exciting sport. One example would be the momentum of a baseball after being released by a pitcher. If Tanaka of the New York Yankees, with a .145kg baseball, threw a 42 m/s fastball towards home plate. You could find the momentum of the baseball by using the equation, P=mv. When plugging in the numbers P= (.145kg)(42m/s), you get momentum to equal 6.09 N*m/s. Furthermore, you can also see the power and the work of Gardner running down first base after making contact with a baseball. Gardner runs down to first base with a force of 800N, which is 27.432m long, at in 2.2 seconds. You can determine his work produced first by using the equation W=Fd. When plugging in the numbers, W=(800N)(27.432m), you find that Gardner produced 21,945.6J of work. Also you can find his power produced by using the equation, P=W/t. After plugging in the numbers, P=(21,945J)/(2.2s), you find that Gardner produced 9,975.27W of power. Overall, I has seen even more connections between baseball and physics in the last couple months, and I hope to find more.
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That's cool, I never knew so much physics applied to dancing. But, you also produce a power and work in dancing too.
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Work at work? of course not
t_hess10 commented on kyraminchak12's blog entry in kyraminchak12's Blog
I've never thought about it that way. Hopefully you stop meeting rude customers and do more exciting "work" at work. -
That's cool. I wonder how much work professional weigh lifters produce when they max out, as well as the work produced to pull a truck.
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Skydiving pretty interesting, but if my parachute didn't open, I would hope that I would have enough air resistance to slow me down enough to stay alive. I wonder how fast someone is actually falling before they pull the parachute.
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Physics in Basketball pt. 3 #ouch
t_hess10 commented on Djwalker06's blog entry in Djwalker06's Blog
I've never thought of how kinetic energy and physics deals with falling. That's a lot of force though hitting that court. -
That's cool. I work out, but I don't think of the physics that applies to working out until now. Now I know that not only is there power involved in working out, but work too.
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Although you don't see many examples of springs throughout our daily lives, one big example is the springs for our cars. You can determine the potential energy of a spring by using the equation PEs = (1/2)kx^2. For example, if a car has a spring constant of 30,000N/m and the spring compresses .1m after landing on the ground, you can determine it's potential energy by multiplying. So, (1/2)(30,000N/m)(.1m)^2 = 150J.
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When watching a 100m dash, I've never thought about the work and power that was used by the runner until now. If the runner exerted 500N of force over the course of the 12 second run, then you can determine the runners work and power. For solving for work, W = Fd. So, (500N)(100m) = 50,000N*m of work done. Then, to solve the power that was used, P = W/t. So, (50,000N*m)/(12s) = about 4,167 Watts of power used.
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I've realized that when looking at a collision, the momentum remains the same in it; however, what we see is the change in velocity. An example would be a 2kg Velcro ball traveling 30m/s that made contact with a 10kg Velcro block initially at rest. When the collision occurred, they stuck together and traveled 5m/s. If you were to look at the momentum before and after the collision, the momentum is the same. Therefore, no matter the type of collision, although the velocity in a collision may vary, the momentum remains the same.
