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jmcpherson82

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Posts posted by jmcpherson82

  1. Okay so here's the problem... Am I approaching this correct?

    "Two boys have a hang time contest on their skateboards. At a speed of 5.0 m/s, they both jump straight up and then land on their moving skateboards. The first boy goes a horizontal distance of 7.5 m before he lands, while the second boy goes 6.0 m before he lands."

    A) How long was each boy in the air?

    B) How high did each boy jump?

    This is what I did..

    D= vt + 1/2 at^2

    5=5x _ 1/2 0 x^2

    5x/5 =7.5/5

    x=1.5 s

    D=vt + 1/2 at^2

    6=5x+ 1/2)x^2

    5x/5=6/5

    x=1.2 s

    A) The two boys were in the air for 1.5 s and 1.2 s .

    D = vt + 1/2 at^2

    D= 5(0.75) + 0 (0,75)^2

    D= 3.75m

    D=vt+1/2at^2

    D=5(0.6)+0(0.6)^2

    D= 3m

    B) Each boy jumped 3.75 m & 3m

  2. Okay, so I know how do usually do these types of problems but I have no idea how to approach this one, could anyone please help me out?

    Vectorville and Scarlartown are 20.0km apart. A cyclist leaves Vectorville and heads for Scarlartown at 20km/h. A second cyclist leaves Scarlartown for Vectorville at the exact same time at a speed of 15km/h. A) Where will the two cyclists meet? B) How much time passes before they meet?

    Just if someone could let me know how to start the problem, that would be fantastic. I think I could figure it out if I just knew where to start. Thanks so much!!

  3. The question is this:

    A hiker sets out on a trek heading (N35degreesE) at a place of 5.0 km/h for 48.0 mins. He then heads west at 4.5 km/h for 40.0 min. Finally, he heads (N30degreesW) for 6.0 km, until he reaches a campground 1.5 hours later.

    A) Find his total displacement using vector components.

    SO, i used Ax = 4.0 cos 35degrees = 3.27

    Ay = 4.0 sin 35degrees = 2.29

    Then I looked at the answers and it said I should have used the angle 55 degree angle instead of the 35. How do I figure out when to use which angle?

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