Data:
V0x= 30m/s
H1= 2.4 m
V0y= 0
X= 12m
H2= 0.9m
To find:
(a) Will the ball clear the net?
( X’= ?
Solution:
(a) X= V0x t
12=30 t
12/30 = t
t= 0.4 s
As, H=V0y t + ½ g t2
H= (0)(0.4)+1/2(-9.8)(0.4)2
H= -0.78m
-ve sign shows that the height of the ball at the net from the top.
Height of the ball at the net and from the ground= H1-H=2.4-0.78=1.62m
As 1.62m>0.9m so the ball will clear the net.
( H1= V0y t’ + ½ g t’2
-2.4= (0)t’ + ½ (-9.8) t’2
.
.
.
t’= 0.69s
X’=V0x t’
X’=(30)(0.96)
X’= 20.7m
This is the solution my teacher came up with and honestly I have no idea whats going on? :/