Search the Community
Showing results for tags 'two'.
Found 3 results
-
Name: 2D Conservation of Momentum Example using Air Hockey Discs Category: Momentum and Collisions Date Added: 2017-05-21 Submitter: Flipping Physics A 28.8 g yellow air hockey disc elastically strikes a 26.9 g stationary red air hockey disc. If the velocity of the yellow disc before the collision is 33.6 cm/s in the x direction and after the collision it is 10.7 cm/s at an angle 63.4° S of E, what is the velocity of the red disc after the collision? This is an AP Physics 1 topic. Want Lecture Notes? Content Times: 0:12 The problem 1:49 Breaking the initial velocity of disc 1 into its components 3:06 Conservation of momentum in the x-direction 5:24 Conservation of momentum in the y-direction 6:26 Solving for the final velocity of disc 2 using its components 8:40 Was this an elastic collision? 12:39 Movie Character Day! Multilingual? Please help translate Flipping Physics videos! Next Video: Introduction to Circular Motion and Arc Length Previous Video: Review of Mechanical Energy and Momentum Equations and When To Use Them! Please support me on Patreon! Thank you to my Quality Control help: Christopher Becke, Scott Carter and Jennifer Larsen "Nombre de los vientos". Licensed under Public domain via Wikimedia Commons - 2D Conservation of Momentum Example using Air Hockey Discs
-
Name: A Range Equation Problem with Two Parts Category: Kinematics Date Added: 19 June 2014 - 01:20 PM Submitter: Flipping Physics Short Description: None Provided Mr.p throws a ball toward a bucket that is 581 cm away from him horizontally. He throws the ball at an initial angle of 55° above the horizontal and the ball is 34 cm short of the bucket. If mr.p throws the ball with the same initial speed and the ball is always released at the same height as the top of the bucket, at what angle does he need to throw the ball so it will land in the bucket? Content Times: 0:14 Reading the problem 1:01 Why we can use the Range Equation 2:15 Listing what we know for the first attempt 3:06 Solving for the initial speed 4:26 Solving for the initial angle 5:45 Putting the ball in the bucket 6:15 There are actually two correct answers 6:44 Getting the ball into the basket Want View Video
-
Name: Understanding the Range Equation of Projectile Motion Category: Kinematics Date Added: 10 June 2014 - 02:03 PM Submitter: Flipping Physics Short Description: None Provided The Horizontal Range of a Projectile is defined as the horizontal displacement of a projectile when the displacement of the projectile in the y-direction is zero. This video explains how to use the equation, why a launch angle of 45° gives the maximum range and why complimentary angles give the same range. Content Times: 0:16 Defining Range 0:50 How can the displacement in the y-direction be zero? 1:21 The variables in the equation 2:09 g is Positive! 3:05 How to get the maximum range 4:17 What dimensions to use in the equation 5:19 The shape of the sin(θ) graph 6:17 sin(2·30°) = sin(2·60°) 7:35 A graph of the Range of various Launch Angles 8:18 The Review Want View Video
-
- example
- equation
- range
- projectile
-
Tagged with:
