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# Motion in 2 Dimensions

## Question

A ball has an intial velocity of 1.30m/s along the +y-axis and starting at t(o), receives an acceleration of 2.10m/s^2 in the x- direction.(a) what is the position of the ball 2.50 s after t(o). b. What is the velocity of the ball at the time ?

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Hi GGirl,

This looks like a great problem to break into separate components of horizontal (x) and vertical (y) motion.

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In the vertical plane, the initial velocity is 1.3 ms, and acceleration is -9.8 m/s2.  Find its y-displacement and y-velocity after 2.5 seconds using your kinematic equations.

In the horizontal plane, the ball's initial velocity is 0, its acceleration is 2.1 m/s2, find its x-displacement and x-velocity after 2.5 seconds using your kinematic equations.

Then, find its total velocity at time t=2.5 seconds by combining the x-velocity and y-velocity vectors.

Good luck!

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Thank you . That was very helpful

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Glad it helped.  Make it a great day!

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