Jump to content
  • 0

Kinematics Question - Check Your Understanding



  1. A motorcycle starts from rest and has a constant acceleration. In a time interval t, it undergoes a displacement x and attains a final velocity v. Then t is increased so that the displacement is

    3x. In this same increased time interval, what final velocity does the motorcycle attain? 

The book says the answer is 1.73 v, but my teacher gave a bunch of variables when he solved it.

Edited by Daemidra
Link to comment
Share on other sites

2 answers to this question

Recommended Posts

  • 1

This question can be solved using one of the Equations of Motion, namely v^2 = u^2 + 2ax where 
v is the final velocity, u is the initial velocity, a is the acceleration and x is the displacement. 

Since the motorcycle starts from zero u =0 and can be discarded from the equation. 
The equation is now v^2 = 2ax 
If the displacement changes to 3x our equation becomes (new v)^2 = 2a3x 
(new v)^2 = 6ax 
but the velocity in the first case was given by v^2 =2ax: (new v)^2 = 3 v^2 
Square root both sides new v = square root of 3 times v 
Square root of 3 is 1.73

From - https://answers.yahoo.com/question/index?qid=20110917100043AAuhgCE

  • Like 1
Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Answer this question...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

  • Create New...