A car is travelling on the highway at a constant speed of 24 m/s. The driver misses the posted speed limit sign for a small town she is passing through. The police car accelerates from rest at 2.1m/s^2. From the time the speeder passes the police car :
A) How long will it take the police car to catch up to the speeder?
Question
FizziksGuy
A car is travelling on the highway at a constant speed of 24 m/s. The driver misses the posted speed limit sign for a small town she is passing through. The police car accelerates from rest at 2.1m/s^2. From the time the speeder passes the police car :
A) How long will it take the police car to catch up to the speeder?
What distance will the car travel in that time?
Car 1 : Car 2:
v_i=24 m/s v_i=0
a=2.1m/s^2
d=vt d=0.5at^2
vt=0.5at^2
2vt=at^2
2(24)t=2.1t^2
48t=2.1t^2
divide both sides by 2.1t
A) 22.9s=t
d=vt=24 m/s * 22.9s = 549m
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