A car is travelling on the highway at a constant speed of 24 m/s. The driver misses the posted speed limit sign for a small town she is passing through. The police car accelerates from rest at 2.1m/s^2. From the time the speeder passes the police car :

A) How long will it take the police car to catch up to the speeder?

## Question

## FizziksGuy

A car is travelling on the highway at a constant speed of 24 m/s. The driver misses the posted speed limit sign for a small town she is passing through. The police car accelerates from rest at 2.1m/s^2. From the time the speeder passes the police car :

A) How long will it take the police car to catch up to the speeder?

What distance will the car travel in that time?

Car 1 : Car 2:

v_i=24 m/s v_i=0

a=2.1m/s^2

d=vt d=0.5at^2

vt=0.5at^2

2vt=at^2

2(24)t=2.1t^2

48t=2.1t^2

divide both sides by 2.1t

A) 22.9s=t

d=vt=24 m/s * 22.9s = 549m

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