By Flipping Physics, 06/10/2014

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The Horizontal Range of a Projectile is defined as the horizontal displacement of a projectile when the displacement of the projectile in the y-direction is zero. This video explains how to use the equation, why a launch angle of 45° gives the maximum range and why complimentary angles give the same range.

Content Times:

0:16 Defining Range

0:50 How can the displacement in the y-direction be zero?

1:21 The variables in the equation

2:09 g is Positive!

3:05 How to get the maximum range

4:17 What dimensions to use in the equation

5:19 The shape of the sin(θ) graph

6:17 sin(2·30°) = sin(2·60°)

7:35 A graph of the Range of various Launch Angles

8:18 The Review

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Content Times:

0:16 Defining Range

0:50 How can the displacement in the y-direction be zero?

1:21 The variables in the equation

2:09 g is Positive!

3:05 How to get the maximum range

4:17 What dimensions to use in the equation

5:19 The shape of the sin(θ) graph

6:17 sin(2·30°) = sin(2·60°)

7:35 A graph of the Range of various Launch Angles

8:18 The Review

Want [url="http://www.flippingphysics.com/range-equation.html"]Lecture Notes[/url]?

Next Video: [color=rgb(0,0,0)][font=Helvetica][size=3][url="http://www.flippingphysics.com/deriving-the-range-equation.html"]Deriving the Range Equation[/url] of Projectile Motion[/size][/font][/color]

Previous Video: [url="http://www.flippingphysics.com/another-projectile-motion.html"]Nerd-A-Pult #2[/url] - Another Projectile Motion Problem

[url="http://www.flippingphysics.com/give.html"]1¢/minute[/url]