{"id":1142,"date":"2012-01-05T08:25:12","date_gmt":"2012-01-05T13:25:12","guid":{"rendered":"http:\/\/aplusphysics.com\/wordpress\/regents\/?p=1142"},"modified":"2012-01-05T08:25:12","modified_gmt":"2012-01-05T13:25:12","slug":"hookes-law","status":"publish","type":"post","link":"https:\/\/aplusphysics.com\/wordpress\/regents\/mechanics\/hookes-law\/","title":{"rendered":"Hooke&rsquo;s Law"},"content":{"rendered":"<p><strong>Ref:<\/strong> <a href=\"http:\/\/www.aplusphysics.com\/regents\">APlusPhysics: RPE<\/a> Ch. 7 <\/p>\n<p><strong>Agenda:     <br \/><\/strong>&#160;&#160; Intro to Hooke&#8217;s Law    <br \/>&#160;&#160; Hooke&#8217;s Law Lab    <\/p>\n<p><strong>HW:<\/strong> Video and Questions, <a href=\"http:\/\/www.aplusphysics.com\/courses\/regents\/videos\/Springs\/Springs.html\">APlusPhysics: Springs,<\/a> due 1\/6 at 3 p.m.    <br \/>&#160;&#160;&#160;&#160;&#160;&#160;&#160; Work and Power WS, due Friday at 3 p.m.<\/p>\n<p>&#160;<\/p>\n<p>An interesting application of work combined with the Force and Displacement graph is examining the force applied by a spring. The more you stretch a spring, the greater the force of the spring&#8230; similarly, the more you compress a spring, the greater the force. This can be modeled as a linear relationship, where the force applied by the spring is equal to some constant time the displacement of the spring. Written mathematically:<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" alt=\"HookesLaw\" src=\"http:\/\/www.aplusphysics.com\/courses\/regents\/WEP\/images\/HookesLaw.gif\" width=\"50\" height=\"24\" \/><\/p>\n<p>F is the force of the spring in newtons, x is the displacement of the spring from its equilibrium (or rest) position, in meters, and k is the <strong>spring constant<\/strong> which tells you how stiff or powerful a spring is, in Newtons per meter. The larger the spring constant, k, the more force the spring applies per amount of displacement.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" style=\"display: inline; margin-left: 0px; margin-right: 0px\" alt=\"Hookes Law Graph\" align=\"right\" src=\"http:\/\/www.aplusphysics.com\/courses\/regents\/WEP\/images\/HookesLawGraph.png\" width=\"230\" height=\"156\" \/><\/p>\n<p>You can determine the spring constant of a spring by making a graph of the force from a spring on the y-axis, and placing the displacement of the spring from its equilibrium, or rest position, on the x-axis. The slope of the graph will give you the spring constant. For the case of the spring depicted in the graph at right, we can find the spring constant as follows: <\/p>\n<p><img loading=\"lazy\" decoding=\"async\" alt=\"Calculate k\" src=\"http:\/\/www.aplusphysics.com\/courses\/regents\/WEP\/images\/kCalcHookes.gif\" width=\"290\" height=\"41\" \/><\/p>\n<p>You must have done work to compress or stretch the spring, since you applied a force and caused a displacement. How can you find the work done in stretching or compressing the spring? By taking the area under the graph. For the spring shown, to displace the spring 0.1m, we can find the work done as shown:<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" alt=\"Hookes Law Work Calculation\" src=\"http:\/\/www.aplusphysics.com\/courses\/regents\/WEP\/images\/HookesWork.gif\" width=\"278\" height=\"24\" \/><\/p>\n<p>&#160;<\/p>\n<p>See if you can use <strong>Hooke&#8217;s Law<\/strong> to determine the spring constant in the problem below:<\/p>\n<p><a href=\"http:\/\/aplusphysics.com\/wordpress\/regents\/wp-content\/uploads\/2012\/01\/image2.png\"><img loading=\"lazy\" decoding=\"async\" style=\"border-bottom: 0px; border-left: 0px; display: inline; border-top: 0px; border-right: 0px\" title=\"image\" border=\"0\" alt=\"image\" src=\"http:\/\/aplusphysics.com\/wordpress\/regents\/wp-content\/uploads\/2012\/01\/image_thumb2.png\" width=\"589\" height=\"421\" \/><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Ref: APlusPhysics: RPE Ch. 7 Agenda: &#160;&#160; Intro to Hooke&#8217;s Law &#160;&#160; Hooke&#8217;s Law Lab HW: Video and Questions, APlusPhysics: Springs, due 1\/6 at 3 p.m. &#160;&#160;&#160;&#160;&#160;&#160;&#160; Work and Power WS, due Friday at 3 p.m. &#160; An interesting application <a class=\"more-link\" href=\"https:\/\/aplusphysics.com\/wordpress\/regents\/mechanics\/hookes-law\/\">Continue reading <span class=\"screen-reader-text\">  Hooke&rsquo;s Law<\/span><span class=\"meta-nav\">&rarr;<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[9,6,13],"tags":[48,315],"class_list":["post-1142","post","type-post","status-publish","format-standard","hentry","category-dynamics","category-mechanics","category-wep","tag-hookes-law","tag-springs"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.6 - 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