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Physics of College


nathanstack15

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Hey y'all,

Chris, a student at Cornell, wakes up at 8:59am for his 9:05 class. If the class is 1.5 km away, at what constant velocity does he need to travel in order to make it to class at 9:05? Neglect air resistance.

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Well, using the equation velocity=distance/time, we can easily calculate this. If the distance is 1.5 km, we can translate this to 1500 meters. If the time he has to travel to class is 6 minutes, neglecting air resistance, he has 360 seconds. Plugging into the equation v=d/t, we have v=(1500)/(360)= 4.17 meters/second. Pretty much chris better haul his one elix booty to class or he aint makin it 

p.s chris sis hot af

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