jmcpherson82
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Yes, I meant to put 7.5 for boy 1, that was a typo. But for part B, isnt that what I did above?

Okay so here's the problem... Am I approaching this correct? "Two boys have a hang time contest on their skateboards. At a speed of 5.0 m/s, they both jump straight up and then land on their moving skateboards. The first boy goes a horizontal distance of 7.5 m before he lands, while the second boy goes 6.0 m before he lands." A) How long was each boy in the air? How high did each boy jump? This is what I did.. D= vt + 1/2 at^2 5=5x _ 1/2 0 x^2 5x/5 =7.5/5 x=1.5 s D=vt + 1/2 at^2 6=5x+ 1/2)x^2 5x/5=6/5 x=1.2 s A) The two boys were in the air for 1.5 s and 1.2 s . D = vt + 1/2 at^2 D= 5(0.75) + 0 (0,75)^2 D= 3.75m D=vt+1/2at^2 D=5(0.6)+0(0.6)^2 D= 3m Each boy jumped 3.75 m & 3m

If the second cyclist started 3 minutes after the first cyclist, would their equations be : x2=20(15km/h)(ta0.05) ta=intial time

Thank you ! That worked out !

Okay, so I know how do usually do these types of problems but I have no idea how to approach this one, could anyone please help me out? Vectorville and Scarlartown are 20.0km apart. A cyclist leaves Vectorville and heads for Scarlartown at 20km/h. A second cyclist leaves Scarlartown for Vectorville at the exact same time at a speed of 15km/h. A) Where will the two cyclists meet? How much time passes before they meet? Just if someone could let me know how to start the problem, that would be fantastic. I think I could figure it out if I just knew where to start. Thanks so much!!

Deciding what Angle to use....HELP PLEASE !!
jmcpherson82 replied to jmcpherson82's question in Homework Help
Thank you very much! This helped a lot 
The question is this: A hiker sets out on a trek heading (N35degreesE) at a place of 5.0 km/h for 48.0 mins. He then heads west at 4.5 km/h for 40.0 min. Finally, he heads (N30degreesW) for 6.0 km, until he reaches a campground 1.5 hours later. A) Find his total displacement using vector components. SO, i used Ax = 4.0 cos 35degrees = 3.27 Ay = 4.0 sin 35degrees = 2.29 Then I looked at the answers and it said I should have used the angle 55 degree angle instead of the 35. How do I figure out when to use which angle?

The question is this: A hiker sets out on a trek heading (N35degreesE) at a place of 5.0 km/h for 48.0 mins. He then heads west at 4.5 km/h for 40.0 min. Finally, he heads (N30degreesW) for 6.0 km, until he reaches a campground 1.5 hours later. A) Find his total displacement using vector components. SO, i used Ax = 4.0 cos 35degrees = 3.27 Ay = 4.0 sin 35degrees = 2.29 Then I looked at the answers and it said I should have used the angle 55 degree angle instead of the 35. How do I figure out when to use which angle?
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