Okay so here's the problem... Am I approaching this correct?
"Two boys have a hang time contest on their skateboards. At a speed of 5.0 m/s, they both jump straight up and then land on their moving skateboards. The first boy goes a horizontal distance of 7.5 m before he lands, while the second boy goes 6.0 m before he lands."
A) How long was each boy in the air?
How high did each boy jump?
This is what I did..
D= vt + 1/2 at^2
5=5x _ 1/2 0 x^2
5x/5 =7.5/5
x=1.5 s
D=vt + 1/2 at^2
6=5x+ 1/2)x^2
5x/5=6/5
x=1.2 s
A) The two boys were in the air for 1.5 s and 1.2 s .
D = vt + 1/2 at^2
D= 5(0.75) + 0 (0,75)^2
D= 3.75m
D=vt+1/2at^2
D=5(0.6)+0(0.6)^2
D= 3m
Each boy jumped 3.75 m & 3m