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The Horizontal Range of a Projectile is defined as the horizontal displacement of a projectile when the displacement of the projectile in the y-direction is zero. This video explains how to use the equation, why a launch angle of 45° gives the maximum range and why complimentary angles give the same range. Content Times: 0:16 Defining Range 0:50 How can the displacement in the y-direction be zero? 1:21 The variables in the equation 2:09 g is Positive! 3:05 How to get the maximum range 4:17 What dimensions to use in the equation 5:19 The shape of the sin(θ) graph 6:17 sin(2·30°) = sin(2·60°) 7:35 A graph of the Range of various Launch Angles 8:18 The Review Want [url="http://www.flippingphysics.com/range-equation.html"]Lecture Notes[/url]? Next Video: [color=rgb(0,0,0)][font=Helvetica][size=3][url="http://www.flippingphysics.com/deriving-the-range-equation.html"]Deriving the Range Equation[/url] of Projectile Motion[/size][/font][/color] Previous Video: [url="http://www.flippingphysics.com/another-projectile-motion.html"]Nerd-A-Pult #2[/url] - Another Projectile Motion Problem [url="http://www.flippingphysics.com/give.html"]1¢/minute[/url]
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This time in our projectile motion problem, we know the displacement in the y-direciton and we are solving for the displacement in the x-direciton. We could you use the quadratic formula and I even show you how, however, I also show you the way I recommend doing it which avoids the quadratic formula. Content Times: 0:14 Reading the problem 0:55 Comparing the previous projectile motion problem to the current one 1:16 Breaking the initial velocity in to its components 1:44 Listing the givens 2:27 Beginning to solve the problem in the y-direction 3:08 The Quadratic Formula! 5:49 How to solve it without using the quadratic formula. Solve for Velocity Final in the y-direction first 6:59 And then solve for the change in time 8:12 Solving for the displacement in the x-direction 9:01 Showing that it works 9:43 The Review Want [url="http://www.flippingphysics.com/another-projectile-motion.html"]Lecture Notes[/url]? Next Video: Understanding the [url="http://www.flippingphysics.com/range-equation.html"]Range Equation[/url] of Projectile Motion Previous Projectile Motion Problem: [url="http://www.flippingphysics.com/nerd-a-pult.html"]Nerd-A-Pult[/url] - An Introductory Projectile Motion Problem Want a Nerd-A-Pult? You can purchase one at: [url="http://marshmallowcatapults.com"]http://marshmallowcatapults.com[/url] [url="http://www.flippingphysics.com/give.html"]1¢/minute[/url]
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Name: Understanding the Range Equation of Projectile Motion Category: Kinematics Date Added: 10 June 2014 - 02:03 PM Submitter: Flipping Physics Short Description: None Provided The Horizontal Range of a Projectile is defined as the horizontal displacement of a projectile when the displacement of the projectile in the y-direction is zero. This video explains how to use the equation, why a launch angle of 45° gives the maximum range and why complimentary angles give the same range. Content Times: 0:16 Defining Range 0:50 How can the displacement in the y-direction be zero? 1:21 The variables in the equation 2:09 g is Positive! 3:05 How to get the maximum range 4:17 What dimensions to use in the equation 5:19 The shape of the sin(θ) graph 6:17 sin(2·30°) = sin(2·60°) 7:35 A graph of the Range of various Launch Angles 8:18 The Review Want View Video
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Name: Nerd-A-Pult #2 - Another Projectile Motion Problem Category: Kinematics Date Added: 03 June 2014 - 12:29 PM Submitter: Flipping Physics Short Description: None Provided This time in our projectile motion problem, we know the displacement in the y-direciton and we are solving for the displacement in the x-direciton. We could you use the quadratic formula and I even show you how, however, I also show you the way I recommend doing it which avoids the quadratic formula. Content Times: 0:14 Reading the problem 0:55 Comparing the previous projectile motion problem to the current one 1:16 Breaking the initial velocity in to its components 1:44 Listing the givens 2:27 Beginning to solve the problem in the y-direction 3:08 The Quadratic Formula! 5:49 How to solve it without using the quadratic formula. Solve for Velocity Final in the y-direction first 6:59 And then solve for the change in time 8:12 Solving for the displacement in the x-direction 9:01 Showing that it works 9:43 The Review Want View Video
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