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Mr.p throws a ball toward a bucket that is 581 cm away from him horizontally. He throws the ball at an initial angle of 55° above the horizontal and the ball is 34 cm short of the bucket. If mr.p throws the ball with the same initial speed and the ball is always released at the same height as the top of the bucket, at what angle does he need to throw the ball so it will land in the bucket? Content Times: 0:14 Reading the problem 1:01 Why we can use the Range Equation 2:15 Listing what we know for the first attempt 3:06 Solving for the initial speed 4:26 Solving for the initial angle 5:45 Putting the ball in the bucket 6:15 There are actually two correct answers 6:44 Getting the ball into the basket Want [url="http://www.flippingphysics.com/range-equation-problem.html"]Lecture Notes[/url]? Next Video: The Classic [url="http://www.flippingphysics.com/bullet.html"]Bullet Projectile Motion[/url] Experiment Previous Video: [url="http://www.flippingphysics.com/deriving-the-range-equation.html"]Deriving the Range Equation[/url] of Projectile Motion "Walk Away" by Bella Canzano from her EP "[url="http://bellacanzano.bandcamp.com/"]A Secret That You Know[/url]" Music used by permission of the artist. 1¢/minute: [url="http://www.flippingphysics.com/give.html"]http://www.flippingphysics.com/give.html[/url]
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Learn how to derive the Range of Projectile. The Horizontal Range of a Projectile is defined as the horizontal displacement of a projectile when the displacement of the projectile in the y-direction is zero. Content Times: 0:12 Defining Range 0:32 Resolving the initial velocity in to it's components 1:49 Listing our known values 2:49 Solving for range in terms of change in time 3:30 Solving for the change in time in the y-direciton 5:18 Combining two equations 6:03 The Sine Double Angle Formula 6:53 The Review Want [url="http://www.flippingphysics.com/deriving-the-range-equation.html"]Lecture Notes[/url]? Next Video: A [url="http://www.flippingphysics.com/range-equation-problem.html"]Range Equation Problem[/url] with Two Parts Previous Video: [url="http://www.flippingphysics.com/range-equation.html"]Understanding the Range Equation[/url] of Projectile Motion [url="http://www.flippingphysics.com/give.html"]1¢/minute[/url]
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Name: A Range Equation Problem with Two Parts Category: Kinematics Date Added: 19 June 2014 - 01:20 PM Submitter: Flipping Physics Short Description: None Provided Mr.p throws a ball toward a bucket that is 581 cm away from him horizontally. He throws the ball at an initial angle of 55° above the horizontal and the ball is 34 cm short of the bucket. If mr.p throws the ball with the same initial speed and the ball is always released at the same height as the top of the bucket, at what angle does he need to throw the ball so it will land in the bucket? Content Times: 0:14 Reading the problem 1:01 Why we can use the Range Equation 2:15 Listing what we know for the first attempt 3:06 Solving for the initial speed 4:26 Solving for the initial angle 5:45 Putting the ball in the bucket 6:15 There are actually two correct answers 6:44 Getting the ball into the basket Want View Video -
Name: Deriving the Range Equation of Projectile Motion Category: Kinematics Date Added: 16 June 2014 - 02:16 PM Submitter: Flipping Physics Short Description: None Provided Learn how to derive the Range of Projectile. The Horizontal Range of a Projectile is defined as the horizontal displacement of a projectile when the displacement of the projectile in the y-direction is zero. Content Times: 0:12 Defining Range 0:32 Resolving the initial velocity in to it's components 1:49 Listing our known values 2:49 Solving for range in terms of change in time 3:30 Solving for the change in time in the y-direciton 5:18 Combining two equations 6:03 The Sine Double Angle Formula 6:53 The Review Want View Video
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The Horizontal Range of a Projectile is defined as the horizontal displacement of a projectile when the displacement of the projectile in the y-direction is zero. This video explains how to use the equation, why a launch angle of 45° gives the maximum range and why complimentary angles give the same range. Content Times: 0:16 Defining Range 0:50 How can the displacement in the y-direction be zero? 1:21 The variables in the equation 2:09 g is Positive! 3:05 How to get the maximum range 4:17 What dimensions to use in the equation 5:19 The shape of the sin(θ) graph 6:17 sin(2·30°) = sin(2·60°) 7:35 A graph of the Range of various Launch Angles 8:18 The Review Want [url="http://www.flippingphysics.com/range-equation.html"]Lecture Notes[/url]? Next Video: [color=rgb(0,0,0)][font=Helvetica][size=3][url="http://www.flippingphysics.com/deriving-the-range-equation.html"]Deriving the Range Equation[/url] of Projectile Motion[/size][/font][/color] Previous Video: [url="http://www.flippingphysics.com/another-projectile-motion.html"]Nerd-A-Pult #2[/url] - Another Projectile Motion Problem [url="http://www.flippingphysics.com/give.html"]1¢/minute[/url]
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Name: Understanding the Range Equation of Projectile Motion Category: Kinematics Date Added: 10 June 2014 - 02:03 PM Submitter: Flipping Physics Short Description: None Provided The Horizontal Range of a Projectile is defined as the horizontal displacement of a projectile when the displacement of the projectile in the y-direction is zero. This video explains how to use the equation, why a launch angle of 45° gives the maximum range and why complimentary angles give the same range. Content Times: 0:16 Defining Range 0:50 How can the displacement in the y-direction be zero? 1:21 The variables in the equation 2:09 g is Positive! 3:05 How to get the maximum range 4:17 What dimensions to use in the equation 5:19 The shape of the sin(θ) graph 6:17 sin(2·30°) = sin(2·60°) 7:35 A graph of the Range of various Launch Angles 8:18 The Review Want View Video