Wind vs Toupee
Here's a question for you physics lovers: A man is walking down the with a toupee weighing .05 kg while strong gust of wind are flying right at him. The coefficient of friction from his head to the toupee is .01. Using -10 as acceleration due to gravity, what force is required for the wind to blow the toupee off his head?
Well if we were to look at the forces acting on the toupee, there is a gravitational force down of mg = .5 N, a normal force up of. 5 N, some force F acting to the right, and the friction force acting to the left, Ff = .005 N. Using right as the positive direction, Net Force = ma, therefore F - Ff = ma. So, F + .005 = .05(10) and with some basic algebra, you get the force F = 4.995 N. There you have it; physics of a toupee. Tune in next post for more crazy physics concepts.
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