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Zumba is a Losing Battle

sara329

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My friends and I go to Zumba classes three times a week and it is very fun. Like any regular physics student, I am constantly thinking about Mr. Fullerton's lessons during class. As we dance, jump, and move I get to thinking... it must take a lot of energy to move around the way we do. But as we eat healthily and exercise more often, Zumba gets easier and easier... why?

Here are some of the equations I will be using to help explain this Zumba Paradox...

- KE = (1/2)(mass)(velocity2)

- PE = (mass)(g)(height)

- Work = Change in Mechanical Energy

- Work = Force * Displacement

It takes work to move our body in all different sorts of ways. Because work is equal to the change in Mechanical Energy, and both Kinetic Energy and Potential Energy are proportional to the mass of the object, it is reasonable to say that work is also proportional to the mass of the object. In this case, the object is our body.

As any athletic trainer will happily tell you, a good workout is one where you do the most work. In our case, we will hold everything else constant besides our mass because we are doing the exact same class every time we work out. Put extremely simply, work is how much you move times how much weight you are moving. So, it is correct to say that as you lose mass you will do less and less work each successive time you go to Zumba class.

I want to lose weight at a constant rate, as would most females in Zumba class. Constant weight loss is much better than fluctuating weight loss. So how can I keep my weight loss constant, and overcome this work-mass relationship that we discussed earlier?

Zumba deals with changes in Kinetic Energy more than other types of fitness training such as weight lifting which deals more with changes in Potential Energy. So for simplicity we will set Work equal to the change in only KE.

Here's what we want to happen:

C = (1/2)(mass)(velocity2) // With C being a constant positive number that represents an amount of Joules

In order for us to keep a constant C, velocity2 has to increase at a rate equal to the rate at which mass decreases.

Here's our relationship in equation form:

velocity2 = 1/mass // or in exponential form --> velocity = mass-1/2

So there it is, ladies and gents, if you want to lose weight at a constant rate, you need to increase your intensity a little bit each class as you shed the pounds.



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That's a really interesting way to think about working out, using work! I would have never thought of that.

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You said "As any athletic trainer will happily tell you, a good workout is one where you do the most work." So wierd to think and understand how "work" actually works in terms of physics. Relating excersize to physics is cool because it gives you alterntiatives or methods to change your work out so that you recieve the results you seek.

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