randomuser Posted June 17, 2016 Share Posted June 17, 2016 A 0.15-kilogram baseball moving at 20 m/s is stopped by a catcher in 0.010 seconds. The average force stopping the ball is: (A) 3.0x10^-2 N (B) 3.0X10^0 N (C) 3.0X10^1 N (D) 3.0X10^2 N The explanation says that it takes 0.010 seconds for the baseball to accelerate from 0 m/s to 20 m/s, but that doesn't really match up with the question... Is the wording a little weird? Quote Link to comment Share on other sites More sharing options...
FizziksGuy Posted June 20, 2016 Share Posted June 20, 2016 I think it says it takes 0.01 seconds for the baseball to accelerate from 20 m/s to 0 m/s, which exactly matches up with the question. Delta-V is V_final - V_initial. Quote Link to comment Share on other sites More sharing options...
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