# FizziksGuy

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2. ## Week 1

Off to a great start!
3. ## AP physics 1 essentials 2nd edition

Yup, great catch! Updating...
4. ## Space Engine

Absolutely beautiful. And you put that first video together? Great dramatic musical selection to go with it!!!
5. ## Ap physics 1 essentials 2nd edition

That is a FANTASTIC question, and to answer it, we need to understand that by accelerating at the top position, we're no longer maintaining a circular orbit, but setting up an elliptical orbit. If we increase the speed of the satellite in that top position, we've increased the kinetic energy of the satellite at that position. But a more complete orbital analysis must take into account gravitational potential energy. By increasing the kinetic energy at the top position, we'll trade that speed off for gravitational potential energy at the bottom position. The following web page goes into more detail (https://www.physicsforums.com/threads/orbital-speed-faster-is-closer.733175/), but the best way I've found to get a good feel for orbital mechanics is to play games. As mentioned on the thread above, Orbiter is a free game that will give you a good feel for it, but Kerbal Space Program is a lot more fun in my opinion (though it's not free). :-)

Hi Scott, The PDF book itself isn't printable due to licensing restrictions, however, you can print out all the original worksheets here: http://www.aplusphysics.com/courses/regents/worksheets/ws_index.html. The answer key is only available in electronic form.
7. ## Ap physics 1 essentials 2nd edition

I'm assuming you're attempting to use v=d/t and coming up with L/t. Recall, though, that this formula gives you AVERAGE velocity. V_f is equal to 2*average velocity under constant acceleration, which you can provide by: v_0=0 v=? d=L a t=t Solve vf^2=v_0^2+2ad to get v_f=Sqrt(2aL) Solve d=v_o*t+.5*a*t^2 to get a=2L/t^2 Combine those two equations to eliminate a and solve for vf to show vf=Sqrt(4L^2/t^2)=2L/t
8. ## Ap physics 1 essentials 2nd edition

I'm not sure I completely understand the question, but if I attempt to read between the lines, you're wondering why this isn't the same as a block sliding down a ramp. Recall for the box sliding down a ramp scenario, we're setting the motion of the box along the x-axis and 'tipping' our axes to line up with that motion. In this case, although it looks like a box on the ramp, the car is actually moving into or out of the page, not sliding down the ramp. The direction of its motion is centripetal as it goes around the curve, or directly to the right (along the x-axis)... so we don't tilt our axis in this problem. As the car's motion is along the positive axis, directly horizontal, that remains our 'reference' axis.
9. ## MRI machine

I'm hoping you get some good news too...
10. ## The Physics of Cruise Ships

Fantastic application of physics in soooo many ways. I'm always floored by aircraft carriers and how they're able to maintain such stability. Big ships are totally cool!