Okay so here's the problem... Am I approaching this correct?

"Two boys have a hang time contest on their skateboards. At a speed of 5.0 m/s, they both jump straight up and then land on their moving skateboards. The first boy goes a horizontal distance of 7.5 m before he lands, while the second boy goes 6.0 m before he lands."

A) How long was each boy in the air?

How high did each boy jump?

This is what I did..

D= vt + 1/2 at^2

5=5x _ 1/2 0 x^2

5x/5 =7.5/5

x=1.5 s

D=vt + 1/2 at^2

6=5x+ 1/2)x^2

5x/5=6/5

x=1.2 s

A) The two boys were in the air for 1.5 s and 1.2 s .

## Question

## jmcpherson82

Okay so here's the problem... Am I approaching this correct?

"Two boys have a hang time contest on their skateboards. At a speed of 5.0 m/s, they both jump straight up and then land on their moving skateboards. The first boy goes a horizontal distance of 7.5 m before he lands, while the second boy goes 6.0 m before he lands."

A) How long was each boy in the air?

How high did each boy jump?

This is what I did..

D= vt + 1/2 at^2

5=5x _ 1/2 0 x^2

5x/5 =7.5/5

x=1.5 s

D=vt + 1/2 at^2

6=5x+ 1/2)x^2

5x/5=6/5

x=1.2 s

A) The two boys were in the air for 1.5 s and 1.2 s .

D = vt + 1/2 at^2

D= 5(0.75) + 0 (0,75)^2

D= 3.75m

D=vt+1/2at^2

D=5(0.6)+0(0.6)^2

D= 3m

Each boy jumped 3.75 m & 3m

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