Honors and Regents Physics

Breaking news just in: physics students at IHS have justcalculated the acceleration due to gravity! Said students had the tallest student hold the ball up in the air. The other students measured the distance fromthe floor to the middle of the ball. Then the tallest student dropped the ball and timed its fall 3times. Then they calculated theacceleration with the formula: a=2d/t^2. They discovered that the acceleration due to gravity is 11.49 m/s^2 withtheir percent error equaling 17.2%! “Thisis a small drop for man, but a greater drop for physics.”

This method had a higher percent error due to the attempt to time the exact moment when someone jumps off the ground and lands on the ground using a stop watch can obtain very inaccurate information. The person timing the person in the air will not know the exact moment of when the person jumps up, with different reactions, and when their feet hit the ground. An accurate version of this expriment can be created by using censors to measure the exact time the person is in the air. There could be a censor anywhere on the body where it would be constant, then the other person could set up a seperate censor to measure the person jumping. This censor could be hooked up to a com…

Determining G: News article This just in! Recently, young physicists at Irondequoit High School have calculated the acceleration due to gravity (g). In doing this, the students were first instructed to use their knowledge on kinematic equations to determine acceleration because of gravity. The students used a tape measure, a ball and a stopwatch to conduct this experiment, performing three trials. First off, the students created a table, filling in what they know. One group in particular came up with data as followed before beginning their experiment: The initial velocity was 0 m/s, and the distance was 2 meters. Then, one student measured out 2 meters with the measu…

This experiment had a large margin of error, due to in part from the equipment used and its mechanical limitations. The stop watch used is extremely hard to time with a person jumping, and just as hard to stop when the person lands back down. In order to eliminate much of the error, a more state of the art piece of equipment can be used to record the data. An infrared beam attached to a computer, with the Logger Pro program on, would more easily record the time of a person jumping and falling back down.

In our group, 16% 23% and 25% were very high percent error results. This is due to the fact that we didn't have a very good form of measuring time. With the stop watches that we used, it is easy to miscalculate and press the start and stop button at the perfect time. If we could set up this experiment again, we would use motion sensor equipment to time when we left the ground and returned exactly. we would also have a measuring tool such as a newer tape measure that isn't old and worn to measure how high we were so our results would be more accurate. If we have better times and meaurements it would be much easier and we would have less of error.

Breaking news out of Irondeqouit High School! Students in Mr. Fullerton's Regents Physics class, using nothing but stopwatches, measuring sticks and a basketball,measured the acceleration due to gravity. Their first order of business was to drop the ball a meter high off of the ground. They then recorded the time it took for the ball to drop to the floor. Using their vast knowledge of physics, they calculated the acceleration of the drop using the formula D=Vit+1/2at(t). Already knowing the distance, initial velocity, and time of the drop, they quickly calculated the acceleration. However, their results were less than optomistic, as their percent errors fell between 41% a…

Recently students in Mr. Fullerton's regents physics class have taken up an important task, calculating the acceleratin due to gravity on the surface of the earth. This question was answerd in a simple manner, by dropping balls on the english classes below them. The known and accepted answer by the scientific community is 9.91 meters per second square, but did these students get that answer? The answer was not exactly that. From two students tests Ben and Gerrard the calculated value was 11 meters a second square. With a 12 percent error this may be the best these students could do with the equipment available. In the future perhaps their will be a better way for high sch…

Physics students in Mr. Fullerton's class conducted an experiment determine the acceleration due to gravity in a free falling object. The students ran through several trials utilizing a ball dropped from a controlled distance, 2 meters, and used a timing device to record the dropped ball's velocity. The students then calculated the average time, finding it to be .563 seconds. With this information in mind the studnets were able to calculate the acceleration due to gravity. Here is the table of variables the students utilized to find the acceleration: Vi = 0 m/s Vf = Not needed A = ? T= .563s By using the kinematic equation a=d/t, the students came to a final acce…

In physics class at Irondequoit High School Students did a lab to show gravity close to the earth’s surface. The students showed that the gravity is approximately 9.73m/s^2. This is a .82% error compared to other research. The students found this out by dropping a ball and timing how long it took for the ball to hit the ground from two meters. As the group of three dropped and timed the ball they recorded the results of the three trials they did. Using the time, distance and initial velocity they found out the acceleration for each time. The group used the kinematics equation ‘d = vit + (1/2)at^2.’ When they rewrote the equation they got ‘a = (d – vit)/((1/2)at^2).’ Afte…

Mr. Jordan Kushel and his cronies Abby Corbett and Alex Shoemaker have recently discovered that gravity accelerates at a rate of 8.82 m/s squared. They’re wrong you say? False! They measured it themselves! False again! It’s actually 9.81 m/s squared but they were within 9% accuracy! WOW! All they did was drop a ball from the top of a two meter stick, and measure the time it took to fall to the ground. Using a simple formula “square root of 2(distance) divided by time = acceleration” and just like that they came up with a wrong answer due to things like timing incorrectly or dropping that ball at different heights. However they tried! Great job guys!

1. the speeding lab is to determine the average speed of cars traveling down cooper road by measuring the meters per second. We are trying to see if cars are speeding and the general average speed down the road. 2. First we measured out 30 meters down the sidewalk. one person stood at 20 meters and another at 30 meters. we measured the times at both places and recorded for 10 different cars. Then we used the equation v=d/t to find the speed and after we calculated the average speed.

Physic Speeding Lab Danielle, Katie, Tori,Victoria Introduction paragraph: In thislab, the problem we were trying to solve is seeing if drivers are travelingover the speed limit on Cooper Road in front of the high school. This area hasa 35 mph speed limit. Our team has been asked to gather data about the carstraveling down Cooper Rd. Step-by-step procedure: 1. We came up with a plan to have two distancepoints in order to get a variety of data. We took a measuring tape and two stopwatches outside and found a place along the road to mark spec…

Car Crash Web Quest Ray Wagner, Pat Suter, Mike LiPani 12/21/11 Physics R (3+4) A traffic accident has just occurred on Millway Street. A 3000 kg Cadillac Escalade SUV has just rear-ended a 2000 kg Subaru Outback at a stop sign. We are trying to determine if the vehicle exceeded the speed limit of 35 km/hr before the time of impact. The results of this investigation will determine the punishment of the SUV driver. We examined the crash site an…

Car Crash Web Quest Challenge Dear Mayor, I am writing to inform you of a traffic accident concerning a 3000 kg SUV and a 2000 kg Subaru Outback Wagon. The accident occurred in a 35 km/hr speed limit zone where the Wagon was stopped at a stop sign. From our data, we can conclude that the SUV was speeding when the driver rear ended the Subaru wagon. We were able to come to this conclusion from our use of kinematics, the momentum of each car, and the law of the Conservation of Momentum. The first step we had to take to figure out if the SUV was speeding or not was to find each car’s velocity immediately after the two cars collided. The …

A traffic accident occurred in a 35 km/hr speed limit area on Millway Street in which a 3000-kg Cadillac Escalade SUV rear-ended a 2000-kg Subaru Outback Wagon that was stopped at a stop sign. The Subaru traveled forward with a distance of 24 meters, the Escalade only traveled 2 meters. We found this information from the skid marks that were left by both the SUV and the wagon. With the amount of distance that was covered by the wagon after the collision, we can assume that the SUV had to be going pretty fast to make the wagon move 24 meters. We calculated the speed of the SUV to be about 39 km/hr, which is 4km/hr over the speed limit. The driver denies that he was speedi…

Car Crash Web Quest A traffic accident occurred in a 35 km/hr speed limit zone on Millway Street in which a 3000-kg Cadillac Escalade SUV rear-ended a 2000-kg Subaru Outback Wagon that was stopped at a stop sign. Because the entire police investigative division has gone on vacation to Bora Bora to relax, the mayor has contracted my team of experts to determine what happened and what traffic laws were broken. Using the little bit of data we were supplied we were able to find out enough information to figure out if the driver of the 3000-kg Cadillac Escalade SUV was speeding. Using our kinematics equations we used the formula Vf^2 = Vi^2 + 2ad to figure out the veloc…

When we arrived at the scene of the crime we found the weight of the SUV at 3000kg and the weight of the Wagon at 2000kg. We also observed skid marks of both vehicles from the impact zone. The SUV had a skid mark of 2m while the Wagon skidded 24m. From this information and our kinematic equation we found the initial velocity by using the equation of vI^2 =vF^2-2ad. With this equation we found the wagon had an initial velocity of 2.82m/s and the SUV had an initial velocity of 12m/s. Using this velocity we found the momenta using the equation mv=P. P meaning momentum. With this equation we learned the the momentum of the SUV immediately following the collision was 8…

Car Crash Web quest write-up In the car crash web-quest, we were given a situation of an accident. The Cadillac crashed into a non-moving Subaru. We were given only the mass of the 2 cars the distance and acceleration they traveled after they collided. The mass of the Cadillac is 3000kg, and traveled 2 meters with acceleration of -2m/s. The Subaru is 2000kg and went 24 meters with acceleration of -3m/s. To find the velocity of the SUV immediately following the collision, we used the formula Vf^2=Vi^2 + 2AD. We used this because we had the final velocity (zero, because it stopped), the distance, and acceleration. We rearranged it to be equal to …

Dylan, Sarah, Joe 12/20/11 In order to find out if the SUV was speeding, we first had to find out the velocity of both the SUV and the wagon immediately following the collision. We found that the velocity of the SUV was 2.83 m/s and the wagon was 12.0 m/s. These values were found by using the kinematics equations to find Vi because we already had enough information to solve for the unknown in Vf^2=Vi^2+2ad. Then, we could find the momentum of the wagon and SUV immediately after the collision using p=mv. The momentum of the SUV was 8490 Kg x m/s and the …

In this challenge a 3000kg SUV hit an Outback Wagon (2000kg) while it was stopped at a stop sign. The SUV skidded 2m while the Outback skidded 24m after being hit. The velocity of the SUV immediately following the collision was 2.83 m/s. The velocity of the wagon immediately following the collision was 12 m/s. We determined these answers by using kinematic equations because we knew the final velocity, acceleration, and distance. Using the equation Vi^2=Vf^2-2ad we were able to solve for Vi to determine the velocity immediately following the collision. Next we determined the momentum immediately following the collision by using P=MV. The momentum of the SUV im…

Car Crash Webquest Challenge Nate, Ryan and Miani Period 8 12/20/11 In a 35 km/hr speed zone, an SUV rear ended a parked station wagon at a stop sign. The SUV traveled 2 meters, and the wagon traveled 24 meters. Using this information and given the brakes decelerated the SUV at -2 m/s and the wagon at -3 m/s, we calculated that the SUV was moving at 2.83 m/s after the collision, and the wagon at 12 m/s. The momentum for the SUV was 8,490 kgm/s, and the wagon was 24,000 kgm/s. Due to the law of the conservation of momentum, the momentum before the collision was equal to the momentum after, so the momenta of the vehicles after the collision added toge…

Physics Jacob, Liz, Alana Period 7/8 12/20/11 Our team will provide the mayor with a detailed accident report that includes mass, velocity, and momentum of both vehicles both prior to and after the collision. Further, the mayor has requested we find out what happened to assist with the insurance company’s investigation. First we found velocities of both car…

Matthew, Stephanie, Dylan physics period 1 CAR CRASH WEBQUEST CHALLENGE In kinematics our goals were to find the velocity of both the SUV and the wagon following the collision. We have found that the velocity of the wagon was greater after the collision at a velocity of 12 meters per second and the SUV’s velocity was 2.8 meters per second. By using momentum we have found that the momentum before the collision, of the SUV’s was 32,400kiligrams meters per second while the wagon was zero since the wagon was at a stop. So from this info we used this to see that if th…

Gunnar Miller, Nick Nolan, Kaiya Williams Car Crash Web quest Next we were required to find the momentum immediately following the collision with our physics knowledge of the formula Momentum=(mass)(velocity) or P=mv we had both vehicles masses and velocity’s prior to the crash. The way we solved was as follows Cadillac: P= (3000kg)(2.83m/s)=8,490kg*m/s Subaru: P=(2000kg)(12m/s)=24,000kg*m/s. after finding these two momentums it played a huge role in solving the rest of the lab. The next part was finding the Momentum before the collision this was a very simple step in the lab we knew that before the collision the Subaru was …

Gunnar Miller, Nick Nolan, Kaiya Williams Car Crash Web quest The car crash web quest included two vehicles a Subaru (200kg) which was at rest and a Cadillac (300kg) which ran into the Subaru. The first objective we tried to solve for was the velocity of both vehicles after the crash. We were given the acceleration of both after the crash which was -3m/s^2 for the Subaru and the Cadillac’s was -2m/s^2. The distance that they went after the collision was also provided Subaru (24m) and the Cadillac (2m). we knew the car cars came to rest after the crash so Vf=0 for both. Once we knew we had three of the five solving for Vi would be simple. We used the formula Vf^2=V…